Ⅳ Functions · Stage 23 — Quadratic Functions · 23.1 Meeting the QuadraticAll lessons →
Stage 23 · Quadratic Functions

23.1  From Functions to Quadratics: Getting Started

A new member of the function family: when the highest power is a square, y = ax² + bx + c (a ≠ 0).

Ages 13–16 · Reasoning, one step at a time
The plainest quadratic, y = x²: square the input and the graph curls into a symmetric bowl — the parabola.

You have already met functions that turn an input into an output by a steady rule — double it, add to it, share it out. But some things grow faster the bigger they get: widen a square photo and its area balloons far quicker than its side. That “side squared” relationship is the first whisper of a new kind of function — the quadratic. This lesson welcomes it into the family, writes its definition y = ax² + bx + c, teaches you to spot a, b, and c, and plots the simplest one so you can see its shape.

23.1.1 Revisiting the function family

A function is one rule that turns each input x into a single output y, written y = f(x). You have already kept company with a few of them — and each one drew its own shape on the coordinate plane (and you learned to read those shapes back in functions and graphs):

Each of these is one rule, one graph. But notice what they all have in common: the input x only ever appears to the first power. Now meet a rule that does something new — it squares the input. As soon as an shows up, the line bends into a curve, and we have a brand-new member of the family.

Different rules, different shapes: the line y = x and the curve y = x² both turn x into y — but squaring bends the graph.
Key idea

A function is one rule, y = f(x), turning each input into a single output. Lines and gentle curves you have met all keep x to the first power. Squaring the input is the new move — and it bends the graph into a parabola.

23.1.2 A new relationship hidden in area

Here is the squaring rule in disguise. A square photo of side x has area S = x². Grow the side one step at a time and watch the area:

side x1234
area S = x²14916
jump in area+3+5+7

The side climbs in equal steps — 1, 2, 3, 4 — but the area leaps unevenly: +3, then +5, then +7. Each extra unit of side adds more area than the last. That accelerating, uneven growth is the signature of squaring, and it is exactly why the graph of S = x² curls upward instead of staying straight.

Try it Grow the square — watch the area climb the parabola
Drag the side x. The point (x, x²) rides up the blue curve; notice how each step adds more area than the one before.
side x
Key idea

When the output depends on the square of the input, growth speeds up the larger x gets, and the graph curves rather than running straight. That is the heart of a quadratic.

23.1.3 Defining a quadratic function

Tidy any such rule into standard shape and it always reads the same way. A quadratic function is any rule that can be written as

y = ax² + bx + c   (a, b, c constants, a ≠ 0)

The ax² term is what makes it quadratic — it is the highest power, and it is the part that bends the graph. The three constants have names you will use again and again:

Watch out

a ≠ 0 is non-negotiable. If a = 0, the x² term vanishes and you are left with y = bx + c — an ordinary straight line, not a parabola. The square must survive for the function to be quadratic.

23.1.4 Spotting a, b, and c

To name a, b, and c, first tidy the expression into the standard shape ax² + bx + c — expand any brackets, collect like terms, write the powers in order — then simply read off the numbers. Missing terms count as 0. Here are four worked tidy-ups:

expressionstandard formabcquadratic?
y = 3x² − 5x + 23x² − 5x + 23−52yes
y = x²x² + 0x + 0100yes
y = 2 − x²−x² + 0x + 2−102yes
y = (x + 1)(x − 2)x² − x − 21−1−2yes
y = 3x + 20x² + 3x + 2032no — linear
y = 1/x + 1not a polynomialno

The two red rows are non-examples: y = 3x + 2 has a = 0, so it is linear; y = 1/x + 1 has x in the denominator, so it is not even a polynomial — there is no x² to call a at all.

Worked example

Read off a, b, c for y = (x + 1)(x − 2). Expand: (x + 1)(x − 2) = x² − 2x + x − 2 = x² − x − 2. So a = 1, b = −1, c = −2, and since a ≠ 0 it is quadratic.

Try it Build a quadratic, read its a, b, c
Dial a, b, c. The expression and the curve update live. Try setting a to 0 — the machine refuses, because a = 0 is not quadratic.
a 1
b −2
c −3

23.1.5 The simplest quadratic, y = x²

Set a = 1, b = 0, c = 0 and you get the plainest quadratic of all, y = x² — square the input, nothing else. Make a small table of values for x from −3 to 3:

x−3−2−10123
y = x²9410149

Plot those seven points and join them with a smooth sweep, and you get a graceful bowl — the parabola. Two things jump out:

Try it The parent parabola and its mirror
Move x₀ left and right. The point and its mirror sit at the same height because (−x₀)² = x₀² — the bowl folds about the y-axis.
x₀ 2
Key idea

y = x² is the parent parabola. Its lowest point is the origin (0, 0), and it folds perfectly about the y-axis. Every other quadratic graph is just this same bowl reshaped, flipped, and slid around the plane — which is exactly the story of the next lesson.

Recap

Exercises

  1. Is y = 4x² − 1 a quadratic function? If so, name a, b, and c.

    Answer

    Yes — there is an x² term and its coefficient is not 0. In standard form it is 4x² + 0x − 1, so a = 4, b = 0, c = −1.

  2. Is y = 5x − 2 a quadratic function? Explain.

    Answer

    No. There is no x² term, so a = 0 — this is a linear function (a straight line), not a quadratic.

  3. Expand y = (x − 3)(x + 1) into standard form and give a, b, c.

    Answer

    (x − 3)(x + 1) = x² + x − 3x − 3 = x² − 2x − 3, so a = 1, b = −2, c = −3.

  4. For y = x², find y when x = −4, and when x = ½.

    Answer

    y = (−4)² = 16; y = (½)² = ¼. (Note (−4)² is positive — squaring removes the minus sign.)

  5. A square has side s. Write its area as a function of s, and find the area when s = 7.

    Answer

    Area A = s² (a quadratic with a = 1, b = 0, c = 0). When s = 7, A = 7² = 49.

  6. The points (2, 4) and (−2, 4) both lie on y = x². What does that tell you about the graph?

    Answer

    Two points at the same height y = 4, equally far from the y-axis (at x = 2 and x = −2), show the graph is symmetric about the y-axis — because (−x)² = x², every input x and its opposite −x give the same output.

🎯 Quick check

Six questions to lock it in. Tap the answer you think is right.

§ For teachers and parents

The big idea. This lesson introduces the quadratic function y = ax² + bx + c (a ≠ 0) as the next member of the function family, after the linear and proportional functions of Stages 20–21. The two anchors are concrete: area grows like the square of the side (uneven, accelerating growth → a curved graph), and the parent parabola y = x² (symmetric about the y-axis, lowest point at the origin). Students should leave able to recognize a quadratic, tidy it into standard form, and name a, b, c. Later families — inverse proportion (Stage 22) and exponential and logarithmic functions (Stage 24) — will extend this same function-machine idea.

Misconceptions to watch. (1) Forgetting that a ≠ 0 — students sometimes call any equation with letters “quadratic.” Stress that the x² term must survive. (2) Confusing b and c, or missing that an absent term means a 0 coefficient (in y = 4x² − 1, b = 0). (3) Believing (−x)² = −x² — emphasize that squaring kills the sign, which is exactly what makes the bowl symmetric and non-negative. (4) Thinking any curved-looking graph is a parabola; the hyperbola y = k/x curves too but is a different family entirely.

Common Core. F-IF.A.1–2 (function notation and evaluation), A-SSE.A.1 (interpreting the parts a, b, c of an expression), F-IF.C.7a (graphing quadratics, intercepts), and F-BF.A.1 (building a function from a situation — here, area as a function of side).

eastmath.com · Stage 23 · 23.1 Meeting the Quadratic · Reasoning, one step at a time